Would someone please help me,?
√[81x^12y^8z^10]
Favorite Answer
√(ab) = √a*√b
For example, √8 = √(4*2) = √4*√2=2√2.
Also, for powers, taking the square root of a number an even power is alway the number raised to 1/2 of the original power (no square root):
√(aⁿ) =aⁿ/²) (if n is even)
(if n is odd, then the answer would be a(ⁿ-¹)/²*√a. This is easier to see with real examples:
√5¹² = 5^6
√5¹³ = (5^6)√5
So, showing your work:
√[81x¹²y^8z¹º] =
(√81)(√x¹²)(√y^8)(√z¹º) =
9(x^6)(y^4)(z^5)
2â[48] + 7â[12] –â[27]
Rationalize the denominator:
2____
â[3] + â[2]
to simplify, you just extract any whole square roots
similarly,
to rationalize the denominator, you multiply by the conjugate
if you use ^ as power