will someone please show me how to do these three problems?
1. Find the x-intercepts. y = x2 – 7x – 2
2. Find the axis of symmetry. y = x2 + 7x + 5
3. Solve by using the quadratic formula. 5×2 + 7x = 4
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ans.3)
x = -b +_ sqrt( b^2 – 4ac) / 2a
the roots are
x = -7 + sqrt(49 – 4 (5)(-4)) / 2*5
and x = -7 – sqrt(49 – 4 (5)(-4)) / 2*5
solving this u get:
x = ( -7 + sqrt of 129)/10 and x = ( -7 – sqrt of 129)/10…..
ans. 1) to find the x-intercepts, put y = 0.
so eq becomes x^2 – 7x – 2 = 0.
now solve using Quadratic formula x = -b +_ sqrt( b^2 – 4ac) / 2a, u get:
the intercepts are x = (7 + sqrt 57)/2 and
x = (7 – sqrt 57)/2.
for the 2nd ques, i dont understand what axis of symmetry means!!
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1. y = 2x-7x -2 ; set y = 0
0 = -5x -2
2 = 5x
x = 2/5
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