i need some help on some math problems..?
1. find the least common multiple of b^3, b^2c, and b^2c^2
2. Add.. (ad/4d^3) + (8/d) +(mx/d^4)
3. simplify write answers with all variables in the denominator.
A) (m^2xym^3x^-5) / (yy^-4m^-3x^2)
B) (x^2y^-2m^-5y^0) / (xxy^2y^-5x^-3)
Favorite Answer
PROBLEM 1:
The least common multiple (LCM) is b^3 c^2 … it’s the product of the b and c’s with the highest powers… b^3 is the highest power that b is raised to… and c^2 is the highest power that c is raised to…
PROBLEM 2:
(ad/4d^3) + (8/d) + (mx/d^4)
In this problem you have to find the LOWEST COMMON DENOMINATOR (LCD)…
the lowest common denominator (LCD) is 4d^4
….so for the first term, you have to multiply both top and bottom by d…. for the 2nd term, you have to multiply both top and bottom by 4d^3…. and for the 3rd term, you have to multiply both top and bottom by 4… like this…
(ad/4d^3)(d/d) + (8/d)(4d^3 / 4d^3) + (mx/d^4)(4/4)
= (ad^2)/4d^4 + (32d^3) / 4d^4 + (4mx) / 4d^4
** now that you have a common denominator, you can add all the numerators together **
= (ad^2 + 32d^3 + 4mx) / 4d^4
PROBLEM 3A:
(m^2 xym^3 x^-5) / (yy^-4 m^-3 x^2)
= 1 / (yy^-4 m^-5 xym^-3 x^7)
PROBLEM 3B:
(x^2 y^-2 m^-5 y^0) / (xxy^2 y^-5 x^-3)
= 1 / (xxy^2 y^-3 m^5 x^-5)
Hope this helps!