given function f(x)=x2-6x+8, find x, if f(x)=0?
given function f(x)=x2-6x+8, find x, if f(x)=0?
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f(x) = x^2 – 6x + 8 = 0
(x-4)(x-2) = 0
so x = 4 or 2
0
f(x) = x^2 – 6x + 8
f(x) = 0
plug 0 for f(x)
0 = x^2 – 6x + 8
factor
look for two numbers that multiply to 8 and add to -6
the two numbers are -2 and -4
since the leading coefficient is 1, plug in the two numbers in factor form (x + a) (x + b)
(x – 2) (x – 4) = 0
set each quanity equal to 0
x – 2 = 0
x = 2
x – 4 = 0
x = 4
so x = 2 or 4
0
just use the quadratic quation. you should get 2 answers
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