Find the slope and y-intercept of y=-3/5x-2?
This is negative three fifths minus two
I can’t understand the concept of finding the slope and the y intercept, can someone explain it to me? I would greatly greatly appreciate it. This is my weakest part in math, and I’m lost and our reading doesn’t do mush for us.
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mx is the slope, sooo —> -3/5 is the slope
b is the y intercept sooo –>-2 is the y int
to graph it you mark a point on the y axis on 2. then you go up three and 5 to the left
The y-intercept is -2, that is where the line crosses the y-axis. You can think of this in another way. The y-intercept is when the x value is zero. Substitute zero for x, this makes y = -2, which is the y-intercept.
so in this equation it is -3/5
the slope is the steepness of the line.
for the y-intercept you set x = 0
y = -3/5(0) – 2
solve and you get y = -2
Y=MX+B
so
Y=3/5-2
Now, the Y intercept is always B, which in this case is (-2).
The slope is always M -3/5, which means go three up and five over on a graph, starting at (0,0)
y-intercept (b) = -2
use the formula y=mx+b…………….mx=the slope b=y-intercept