Can someone help me with this chem problem?

You add an excess of a base solution, lets say dilute Na-R to the acid solution let say dilute R-Cl. The acid and base will form a salt R-NaCl-R. Choose a salt that solidifies out of solution for titration. You will be able measure the weight of this salt and determine the amount of Cl in the material by determining the molecular weight of the salt molecules. Other salt solids can be determined by figuring the molecular weight of the known compounds. Then determine the amount that was the acid from this total.

It’s like this. Lets say you have an unknown number of girls (acid) in a room. You can send in an excess of guys (base). As soon as they couple up they exit the room to be collected (titration). Any guys w/o a girl stay in the room.

You know all the guys weigh 200 Lbs and all the girls weigh 100 lbs. You weigh all the couples together cause they can’t be separated due to the forces of bonding. divide by the couple weight (molecular weight) and this number is how many girls were there to start with.

I hope you don’t view this as an insult to your intelligence, that’s not how I meant it.

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I am not sure but here goes …

No. of moles = volume * molarity

When u titrate the no of moles of acid are equal to no of moles of base

We know the molarity and volume of the base, and the titration allows us to work out the volume of acid

So i think the expression would be molarity of acid = (molarity of base* volume of base) / volume of acid

I hope that helps!

Oh lord!! I had chemistry in my past…..back when i was a sophomore i believe….I feel your pain.

Im sorry sweetie, i cant help you, i never really understood Chemistry….what i used to do though is go in the morning before class stated and ask the teacher personally for a bit of help to guide me better in taking an approach to solve the question.

Im sorry i couldnt help much, but i wish u the best luck!!

=)