How do you divide and simplify [(x^2 – 3x + 2) / (x^2 – 4x +4)] ÷ [(x^2 – 2x + 1) / (3x^2 – 12)]?
i know you factor them first and then flip (x^2 – 2x + 1) / (3x^2 – 12)but the thing that throws me off is 3x^2-12 all i can get is
this [(x-2)(x-1)/(x-2)(x-2)] ÷ [3(x^2-4)/(x-1)(x-1) then i get stuck
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this is my version =)
[(x^2 – 3x + 2) / (x^2 – 4x +4)] ÷ [(x^2 – 2x + 1) / (3x^2 – 12)]
__flip them first
= [(x^2 – 3x + 2) / (x^2 – 4x +4)] x [(3x^2 – 12) / (x^2 – 2x + 1)]
__factor them
= [(x-2)(x-1) / (x-2)(x-2)] x [(3)(x^2-4) / (x-1)(x-1)]
= [(x-2)(x-1) / (x-2)(x-2)] x [(3)(x-2)(x+2) / (x-1)(x-1)]
__cross them
= [(x-2)(x-1) x (3)(x-2)(x+2)] / [(x-2)(x-2) x (x-1)(x-1)]
= (x-2)(x-1)(3)(x-2)(x+2) / (x-2)(x-2)(x-1)(x-1)
= (x-2)(x-1)(3)(x-2)(x+2) / (x-2)(x-2)(x-1)(x-1)
__simplify them
= (3)(x-2)) / (x-1)
= (3x-6)/(x-1)
hope this help! good luck 4 ur homework! =)
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You cant
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