physics help needed!?
Please WRITE the formula used to solve this problem and THROUGHLY go through the math solving step by step.
Favorite Answer
Xf = .5at^2 + Vt + Xi
Xf = final postition
a = acceleration
t = time
V = intial velocity
Xi = intial postion
Since the car starts from rest, and its initial position is 0m, we don’t need Vt + Xi part
so, Xf = .5at^2
Xf = .5(2)(12)^2
Xf = 144m
144m is the distance the car travel up the hill. To find te horizonal distance and vertical distance use trig
Draw a triangle with the hypotenue of 144m. The ange is 5.5 degrees
sin(theta) = opposite / hypotenue
cos(theta) = adjacent / hypotenue
The horizonal distance is the adjacent piece. The vertical distance is the opposite piece. Let X be the horizonal distance and let y be the vertical distance
sin(5.5) = X / 144
X = sin(5.5)144
X = 13.8m
cos(5.5) = Y/144
Y = cos(5.5)144
Y = 143.34m
