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amirhossein k

plas answer my question.pla,pls,pls?

An airline charter flight requires a minimum of 80 passengers and charges RM250 for a particular flight when exactly 80 people fly. However, the fare will be reduced by RM5 (per person) for each passenger over 80. If the plane can hold a maximum of 120 passengers, find an expression for the revenue obtained by the charter company when N people fly.

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Purple

Favorite Answer

SPUNKIEPINK85, either help out or get out of the way. This is the section where people can ask for homework help, thus the title of the section – “HOMEWORK HELP”. This kid is looking for help. Your type of response is what keeps kids from comfortably asking questions, whether at school or at home, which is what they need to do in order to learn. Nothing says MATURE like someone calling a kid with a question dumb or lazy. To just post in order to insult him makes YOU dumb and lazy, not the other way around. Idiot.

AMIRHOSSEIN K, I hope you ignore his stupid comment. There’s absolutely nothing wrong with your question.

Here’s an explanation:

If 80 people fly, they are charged RM250, therefore:

80 x RM250 = RM20,000.

So, if the airline has 80 passengers, the revenue (the money the airline will make) will be RM20,000.

However, after the 80 people are charged, every person after that will get a discount of RM5, therefore paying RM245. So, since the plane can hold a maximum of 120 passengers, if we assume the plane is going to be full, we have:

120 passengers – 80 passengers = 40 passengers

Therefore, 40 passengers will get the RM5 discount and will be charged RM245 each.

40 passengers x RM245 = RM9,8000

So:

The revenue from 80 passengers is RM20,000

The revenue from 40 passengers is RM9,800

RM20,000 + RM9,8000 = RM29,800

So If N is 120 (i.e. 120 passengers), the revenue obtained by the company is RM29,800:

N = 120

80 passengers x RM250 = RM20,000

120 passengers – 80 passengers = 40 passengers

40 passengers x RM245 = RM9,800

RM20,000 + RM9,800 = RM29,800

If N is, let’s say, 99 (i.e. 99 passengers), the revenue obtained by the company is RM24,655

If N = 99

80 passengers x RM250 = RM20,000

99 passengers – 80 passengers = 19 passengers

19 passengers x RM245 = RM4,655

RM20,000 + RM4,655 = RM24,655

Hope that helps.

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spunkiepink85
wow, kids are so darn dumb and lazy nowadays.
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