I need help for algebra !!! Please give me answers?
ay-b=c solve for y
a(y+1)=b solve for y
ax+b=cx solve for x
ay+z=am-ny solve for y
The digits below are in a special order. What order is it?
0,2,3,6,7,1,9,4,5,8
Favorite Answer
1 y=(c+b)/a
2 y=b/a -1
3 b/(c-a)=x
4 y=(am-z)/(a+n)
5 sorry dont remember that
ay – b = c
first add “b” to both sides… like this…
(ay – b) + b = c + b
now combine “like” terms… to get…
ay = c + b
now divide both sides by “a”
(ay)/a = (c + b) / a…. and the “a’s” cancel out on the left side…
y = (c + b) / a
PROBLEM 2:
a(y+1)=b solve for y
a * y + a * 1 = b
ay + a = b
now SUBTRACT “a” from both sides… like this…
(ay + a) – a = b – a
combine “like” terms… to get…
ay = b – a
now divide both sides by “a”
(ay)/a = (b – a) / a…. and the “a’s” cancel out on the left side…
y = (b – a) / a
y = b/a – a/a
y = b/a – 1
PROBLEM 3:
ax+b=cx solve for x
you want to move all the x’s to either the left or right side…
I’m going to move them to the left side…
ax + b = cx
subtract “cx” from both sides… like this…
(ax + b) – cx = cx – cx
combine “like” terms to get…
ax + b – cx = 0
now subtract “b” from both sides… like this…
(ax + b – cx) – b = 0 – b
combine “like” terms… to get…
ax – cx = -b
now factor out x on the left side…. like this…
x(a – c) = -b
now divide both sides by “(a-c)”… like this…
x(a – c) / (a-c) = -b / (a – c)
the (a-c)’s on the left cancel each other out…
and you are left with…
x = – b / (a – c)
PROBLEM 4:
ay + z = am – ny
you want to get all the y’s on one side… I will put them all on the left side…
ay + z = am – ny
add “ny” to both sides…
(ay + z) + ny = (am – ny) + ny
combine like terms…
ay + z + ny = am
subtract “z” from both sides…
(ay + z + ny) – z = am – z
combine like terms…
ay + ny = am – z
factor “y” on left side…
y (a + n) = am – z
divide both sides by (a+n)
y = (am – z) / (a + n)
PROBLEM 5:
0, 2, 3, 6, 7, 1, 9, 4, 5, 8…
They are 1-digit numbers in reversed alphabetical order
Zero, Two, Three, Six, Seven, One, Nine, Four, Five, Eight…
ay=c+b
y=(c+b)/a
a(y+1)=b
y-1=b/a
y=(b/a)-1
ax+b=cx
ax-cx=-b
x(a-c)=-b
x=-b/(a-c)
ay+z=am-ny
ay+ny=am-z
y(a+n)=am-z
y=(am-z)/(a+n)
i hope can help u larr…another one i also donno..