Find the equation of a line..?

equation of any line through a point specified is

(y-y1)=M*(x-x1)

Since need to be parrallel, then slope is same as other equation. Y=Mx+B Y=-3X+5, slope -3

(Y-1)= -3(x-10)

Y=-3x+31

It has to be parallel (or the same slope)=> 3x+y=constant

and has to have the point (10,1)=> 3*(10)+1=31

=> 3x+y=31

When you see the words points and slope and are asked to identify if they are parallel, use point-slope equation. Before I can put your equation into this form., I must do some manipulations to it.

First, Turn your equation into slope-intercept form.

To do this, use the slope-intercept form, y = mx+b by subtracting the 3x from both sides of the equation. Your line should look like:

Y = -3x+-5

Because we have two negative signs on the same side of the equation, turn them into positive signs. Your line should look like:

Y = 3x+5

Step 2: use the point-slope formula to find out if each equation has the same slope.

Point slope equation.

(y-y1) = m(x-x1)

Plug in your y1 and x1 values into the equation.

(y-1) = 3(x-10)

Distribute the 3 to all numbers inside the parenthesis on the right side of the equation.

(y-1) = 3x-30

Are the two equations parallel?

Yes.

Explanation

These equations have the same slope of 3x and are therefore considered parallel to each other.

you can find the y and x intercept and plant the 2 points with a line through it. the x intercept is 3/5 and the y intercept is 5. plant these cordinates. (3/5,0) (0,5)