x^3+18x^2+45x=0 (solve equation by factoring)?
x^3+18x^2+45x=0 (solve equation by factoring)?
Top 3 Answers
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Factor out an x, and get:
x(x^2+18x+45)=o
one solution is x=0
divide both sides by x, and you get
x^2+18x+45=0
factor:
(x+15)(x+3)=0
so, solutions are x=-15, x=-3, x=0
1
x=0; x=-3; x=-15
take out like factor which is x of your original equation…(x)(x^2+18x+45)=0…then factor the 2nd paran…(x+3)(x+15)…then find each paran equal to 0…x=0; x+3=0, x=-3; x+15=0,x=-15…plug in your answers and check your work
0
x(x+15)(x+3)=0
Thus x can equal 0, -15, or -3.
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