written in simplest form, the expression below is equivalent to what?
9x^2-3x / 1-9x^2
A. -3x / 1+3x
B. 3x / 1+3x
C. -6x / 1+3x
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A is correct
9x^2-3x / 1-9x^2
take 9x^2 out
=[9x^2(1-(3x/9x^2))] / [9x^2(1/9x^2 – 1)]
get rid of 9x^2
=[1-1/3x]/[1/9x^2 -1]
simplify
=[(3x-1)/3x] / [(1-9x^2)/9x^2]
combine and simplify
=[3x(3x-1)] / (-) 9x^2 – 1)
= (-3x)(3x-1)/(3x-1)(3x+1)
expand denominator then get rid of 3x -1 (next step)
= – 3x/(3x+1)
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Answer is A.
Top expression is 3x*(3x-1).
Bottom is (1-3x)*(1+3x)
In order to cancel terms multiply both top terms by -1 (since -1*-1=1) and top becomes -3x*(1-3x). Cancel (1-3x) from top and bottom. Leaves -3x/(1+3x)
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A. -3x / 1 + 3x
How to solve:
(9x^2 – 3x) / (1 – 9x^2)
[-3x ( -3x + 1)] / [(1 + 3x)(1 – 3x)]
[-3x ( 1 – 3x)] / [(1 + 3x)(1 – 3x)]
-3x / (1 + 3x)
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5 years ago
The phrase is a formal or scholarly version of “whether it is.” Grammatically speaking, it’s correct to use the subjunctive “be” in this sentence, but these days very few people really know English grammar. As a college professor, I do use this kind of phrase with colleagues.
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