Please check solution?
If f(x) = x – 2 and g(x) = x^2 – 5, determine f(x^2 – 5) – 3g(x + 1)
(x^2 – 5) – 2 – 3 (x + 1)^2 – 5
= x^2 – 7 – 3x^2 – 6x – 3 – 5
= -2x^2 – 6x – 15
thanks
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You need to distribute the 3 throughout the whole g(x+1).
g(x+1) = (x+1)^2 – 5 = (x+1)(x+1) – 5 = x^2 + 2x + 1 – 5 =
x^2 + 2x – 4; now times 3 is 3x^2 + 6x – 12
Your first part was right.
So it’s x^2 – 7 – (3x^2 + 6x – 12) = -2x^2 – 6x + 5
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