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Anonymous

physics help needed!?

Staring from rest, a car accelerates at 2.0 meters per second squared up a hill that is inclind 5.5 degrees above the horizontal. How far ((a))horizontally and ((b)) vertically has the car traveled in 12 seconds?

Please WRITE the formula used to solve this problem and THROUGHLY go through the math solving step by step.

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use this equation

Xf = .5at^2 + Vt + Xi

Xf = final postition

a = acceleration

t = time

V = intial velocity

Xi = intial postion

Since the car starts from rest, and its initial position is 0m, we don’t need Vt + Xi part

so, Xf = .5at^2

Xf = .5(2)(12)^2

Xf = 144m

144m is the distance the car travel up the hill. To find te horizonal distance and vertical distance use trig

Draw a triangle with the hypotenue of 144m. The ange is 5.5 degrees

sin(theta) = opposite / hypotenue

cos(theta) = adjacent / hypotenue

The horizonal distance is the adjacent piece. The vertical distance is the opposite piece. Let X be the horizonal distance and let y be the vertical distance

sin(5.5) = X / 144

X = sin(5.5)144

X = 13.8m

cos(5.5) = Y/144

Y = cos(5.5)144

Y = 143.34m

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