physics help?
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2. a crow is flying horizontally with a constant speed of 2.70 m/s when it releases a clam from its beak. the clam lands on the rocky beach 2.10 seconds later. just before the clam lands, what is the (a) its horizontal coment of veocity, and (b) its vertical component of velocity, (c) how would your answers to part (a) and (b) change if the speed of the crow were increased? explain.
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please write the formula and the steps.
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I’VE TRIED SOLVING IT ALREADY FOR ANY ONE WHO INSIST I DO IT MYSELF BECAUSE ITS MY HOMEWORK. BUT MY ANSWER DID NOT MAKE SENSE AT ALL.
Favorite Answer
So, for number 1. Te divers run horizonally off the end of a diving board. As soon as the diver jumps off, there are two velocity components. Initial horizonal velocity (1.75 m/s) and intial vertical velocity (0m/s)
Vf^2 = 2ad + Vi^2
Vf = final velocity
a = acceleration
d = displancement (or change in position)
Vi = inital velocity
Vf^2 = 2 (-9.8) (0 – 3) + 0^2
Vf^2 = 58.8
Vf = 7.67 m/s
If the question ask for the vertical speed at which the diver enters the water then, 7.67 m/s is the answer. If the question ask for the speed at which the diver enters the water at an angle then just use pythagarean theorem
a^2 + b^2 = c^2
7.67^2 + 1.75^2 = c^2
c = 7.86 m/s
2)
Reminder: Horizonal motion and Vertical motion are indenpendent of each other. Even if the crow stays still , increases its speed, or slows down, the vertical motion won’t be affected
a) 2.70 m/s
b) 0m/s
if the speed of the crow increases, then its horizonal velocity will increase but not the vertical velocity, it stays the same.
