math question?
add six tenths; fourteen and eighty-nine hundreths; and one hundred twelve and three tenths.
can you show me how u got the answer?
Top 4 Answers
Favorite Answer
You have to change them all to top-heavy fractions, that are all the same, like 32/x.
So, 60/100 + 1489/100 + 11203/100.
Then, add all of the numerators,
60 + 1489 + 11203 = 12752
So, you have 12752/100.
Then, divide the numerator by the denominator – which gives you the whole number – and the remainder goes above the denominator, 127 and 52/100.
Happy mathing =)
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Here are the steps:
(6/10)+14(89/100)+112(3/10)
= (6/10)+(1489/100)+(1123/10)
Take 100 as common denominator and LCM
= (60+1489+11230)/100
=12779/100
=127.79
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if i got that right, you’re asking 6/10 + 14 89/100 + 112 3/10 =?
then that would be 0.6 + 14.89 + 112.3 = 127.79
0
0.60
+ 14.89
————
15.49
+ 112.30
————-
127.79 <---- Answer Use 0's a a place holder when the number of digits are not the same. This also helps the problem line up better, thus easier to work with.
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