math qn. no.1…?

The hypotenuse would be 12 the base would be x and the other side would be 10…

12^2 – 10^2 = C^2

144-100 = C^2

44 = C^2

C= square root of 44

Ok draw yourself a picture.

1)Draw a straight line and label it 10m because that is the distance from the ground to the point 10 meters high

2)Draw the ladder leaning from the top of the ten meter line to the ground. We know this is 12 meters because we were given the length of the ladder.

3) Finally complete the triangle by drawing a horizontal line connecting the two others. This is the line measuring the distance from the wall.

We have a horizontal and vertical line in this triangle that make a 90 degree angle so it must be a right triangle. Therefore we can use the pythagorean theorum to solve it.

if a^2+b^2=c^2

we know c is the hypotenuse and that would be our ladder so thats 12 meters

lets say the one we’re solving for is “a”

and therefore make b 10 meters

plug them in and get a^2+(10)^2=(12)^2

solve for a^2 and take the square root.

Using Pythagorean theorem,

(12*12)-(10*10)=144-100

=44

Distance from the ladder to the wall=square root of 44

pythagorean theorem states that all right triangles’ sides follow this formula: c^2 (square of the length of the hypotenuse) = a^2 + b^2 (sum of the squares of the two other sides)

c = 12

a = 10

find b:

12^2 = 10^2 + b^2

144 = 100 + b^2

44 = b^2

b = 6.63 m

you are able to initiate with a triangle of vertexes D, A, C the place D is a left suitable nook DA=3 cm (vertical), CD is 4 cm (horizontal) and AC is hypoyanuse (5cm) together as D, A , C are 3 corners, B is forth nook of quadrilateral (that’s ultimate nook of quadrilateral!) evaluate ‘D’ is commencing place x,y (0,0) and C= 4,0 A= 0,3 As diagonals are perpendiculars diagonal BD will divide diagonal AC by a ratio of three^2 : 4^2 enable diagonals intersect at E and Diagonal AC chop up as AE : CE = 3^2 : 4^2 and AE+CE = 5 hence AE = 5* 9/25 = a million.8 and CE= 5 -a million.8 =3.2 …..(a million) next step In acceptable perspective triangle BCE given information—>BC= 5 (Hypotanuse) and yet another area is 3.2 …..(a million) So EB= squarert (5^2-3.2^2) = 3.842 hence lacking lenth AB of quadrilateral is squarert (3.842^2 +a million.8^2) = 4.2426 length AB= 4.2426 cm Regards!

12^2 = 10^2 + x^2

x^2 = 144 – 100

X^2 = 44

x = sqrt (44)

x = 6.63325

Katie is right, can`t add any more to it.