I need to know how to solve the system of equations 2x+5y=1 and -x-3y=2 by using inverses of matrices?
yea, difficult right?
so i know how to do a 2×2 matrix but i have no idea on a 2×3. Any idea’s or website help?
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by using all the coefficient of the equations
[. 2 … 5 ] .. [ x ] = [ 1 ]
[ -1 … 3 ] …[ y ] = [ 2 ]
find the inverse. Use this formula:
[ a … b ]
[ c … d ]
Inverse:
[ d .. -b ] multiply to 1/(ad – cb)
[ -c .. a ]
[ 2 … 5 ] ==> [ -3 … -5]
[ -1 … -3 ] ==> [ 1 … 2 ]
[ 2 … 5] ==> 1 / (2*-3 – (-5)*1) = -1
[-1 .. -3]
so the inverse is:
[ -3 … -5] multiply to -1
[ 1 … 2 ]
[3 … 5 ]
[ -1 .. -2]
now multiply to the constant
[ 3 … 5] [1]
[ -1 .. -2] [2]
[ 3 * 1 + 5 * 2]
[-1 * 1 + -2 * 2]
[13]
[-5]
so x = 13 and y = -5
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try doing it with a different method first like substitution and use the answer to try to understand how you would get that with inverses of matrices.
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y = -5
x = 13
if that helps.
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WTF!!!!!!?????? I would look it up on Google.
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