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xslayergirl400x

i need some help on some math problems..?

if you can answer any of these for me and show the work it would be much appreciated..

1. find the least common multiple of b^3, b^2c, and b^2c^2

2. Add.. (ad/4d^3) + (8/d) +(mx/d^4)

3. simplify write answers with all variables in the denominator.

A) (m^2xym^3x^-5) / (yy^-4m^-3x^2)

B) (x^2y^-2m^-5y^0) / (xxy^2y^-5x^-3)

Top 1 Answers
blueskies

Favorite Answer

Here’s the help you asked for… PLEASE try to understand completely how these problems are solved so that you can do them on your own without any help.

PROBLEM 1:

The least common multiple (LCM) is b^3 c^2 … it’s the product of the b and c’s with the highest powers… b^3 is the highest power that b is raised to… and c^2 is the highest power that c is raised to…

PROBLEM 2:

(ad/4d^3) + (8/d) + (mx/d^4)

In this problem you have to find the LOWEST COMMON DENOMINATOR (LCD)…

the lowest common denominator (LCD) is 4d^4

….so for the first term, you have to multiply both top and bottom by d…. for the 2nd term, you have to multiply both top and bottom by 4d^3…. and for the 3rd term, you have to multiply both top and bottom by 4… like this…

(ad/4d^3)(d/d) + (8/d)(4d^3 / 4d^3) + (mx/d^4)(4/4)

= (ad^2)/4d^4 + (32d^3) / 4d^4 + (4mx) / 4d^4

** now that you have a common denominator, you can add all the numerators together **

= (ad^2 + 32d^3 + 4mx) / 4d^4

PROBLEM 3A:

(m^2 xym^3 x^-5) / (yy^-4 m^-3 x^2)

= 1 / (yy^-4 m^-5 xym^-3 x^7)

PROBLEM 3B:

(x^2 y^-2 m^-5 y^0) / (xxy^2 y^-5 x^-3)

= 1 / (xxy^2 y^-3 m^5 x^-5)

Hope this helps!

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