i need some chemistry/math help?!?!?!?!?
here is the question…..Air is 21% oxygen in volume; oxygen has a density of 1.31 g/L. What is the volume, in liters, of a room that contains 60.0 kg of oxygen?
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That’s your problem. Plus the teachers expect YOU to figure out the answer.
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room has 60 KG of O2, = 60000 G
At 1.31 G/L
60000/1.31 = 45801 Liters
if room has 45801 L of O2, and Air is 21% O2
then 21/45801=100/X or Total liters in room is X=45801/.21 = 218102.5L
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Volume of oxygen in room=60000/1.31 litres
Volume of room=(60000/1.31)*100/21000 cubic meters.
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i havent done this for quite a while so i think i might not be 100% correct.
to find the volume u need the moles for O2 first.
so n=m/mr (moles = mass(g)/molar mass)
n=60000/(16*2)
n=1875mol
and then to calculate the volume:
v=n*vm (volume(litre or dm3)=moles*22.4)
22.4 is that other number i cant remember what it’s called
v=1875*22.4
v=42litres
thats it… i hope it’s correct. btw if u dunno what im typing here because im using british system so in america it might be different.
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