I need an answer quick, but it has to be good!!!?

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x(x +3) x(x +3)

since the denominators are common we need’nt take L.C.M

2x+5x(5x+5)

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x(x+3)

2x+25x^2+ 25x

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x(x+3)

taking x common from numerator and denominator

and cancelling them

25x + 27

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x + 3

2x/x(x+3) + 5x(5x+5)/x(x+3)

Lets look at the bottom figures, which are identical

multiply the x and the (x+3) and you get x^2 + 3x (x squared plus 3 x)

Now the top. 5x multiplied by 5x +5 gives you 5x^2 +5x

5x^2 +5 x +2x = 5x^2 +7x

When you add fractions the bottom stays the same… ie 1/4 + 1/4 = 2/4 or 1/2… so your final answer is 5x^2 + 7x / x^2 +3x

now, i’m not sure if the x^2’s cancel each other out if you have to reduce the figure, but that’s the best I can say.

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x(x+3) x(x+3)

First, multiply the (). You get 25x squared+ 25x on top

and x squared + 3x on the bottoms.

Then, since the bottoms are the same, just combine them, like 2/3 plus 1/3 equals 3/3, right?

So, you get 25x squared plus 25 x plus the 2x, on top, or 25 x squared plus 27x, on top,

and x squared +3x on the bottom.

Take out the x equals x(25x+27) on top,

x(x+3) on bottom

Divide both by x equals 25x+27 over x+3