How do you solve x = (3/x) +2?
please dont just post the answer, i can find that, i need to know the steps in solving. im really stuck.
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x = (3/x) +2
Multiply each side by x:
x^2 = 3 + 2x
Subtract 3 + 2x from each side:
x^2 – 2x – 3 = 0
Factorise:
(x – 3)(x + 1) = 0
Equate each factor in turn to zero:
Either:
x – 3 = 0
Add 3 to each side:
x = 3
or
x + 1 = 0
Subtract 1 from each side:
x = -1.
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i believe this is how u answer the problem.
x=(3/x)+2 ===> x-2= 3/x ===> x(x-2)=3 ===> x^2 -2x=3 ===> x^2-2x-3= 0 ===> solve for x by factoring ===> (x-3)(x+1)=0
so the answer should be 3 and -1.
because it is a quadratic equation, it has two answers. the answers check out, so i’m pretty sure they are correct.
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x = (3/x) + 2
Multiply both sides by x:
x^2 = 3 + 2x
Subtract (3 + 2x) from both sides
x^2 – 2x – 3 = 0
(x – 3)(x + 1) = 0
Either:
x – 3 = 0
x = 3
or
x + 1 = 0
x = -1.
0
