How do you divide and simplify [6x / (x – 2)] ÷ 3x?

i’ll try ro help:

[6x / (x – 2)] ÷ 3x

= [6x / (x – 2)] ÷ (3x / 1)

__flip it

= [6x / (x – 2)] x (1 / 3x)

__cross them

= (6x)(1) / (x-2)(3x)

= (6x) / (x-2)(3x)

__simplify them, divide 6x with 3x

= 2 / (x-2)

hope this help! =)

When you are dividing by something, than that is the SAME AS multiplying by the “reciprocal” (flip)

SOOO… you rewrite ” ÷ 3x ” as…… ” TIMES 1/(3x) ”

so…

[6x / (x – 2)] ÷ 3x is the same as [6x / (x – 2)] TIMES 1/(3x)

6x………1

——- * ——- = ?

(x-2) … 3x

notice that you have x on top… and x on bottom… those 2 x’s cancel each other…

Now 6 / 3 is equal to 2, right?

So your answer is…

2

—–

(x-2)

Multiply it out, and you get 6*X on the top and 3*X*(X-2) on the bottom.

The X on top and the X on bottom cancel out. Then note that 3 goes into 6 2 times. You end up with:

2/(X-2)