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gloriousnina

How do simlify these equations?

1. (x^3+2x^2+3x-6)/(x-1)

2. (n^3-27)/(n-3)

Top 2 Answers
minivann

Favorite Answer

okay it took me forever, lol, not really, and my mom who is a math teacher (you can tell its summer in my house, lol)…

if you have to show ur work here it is…

x-1(division bar —) x^3+2x^2+3x-6 this allows easy set up

and then just divide one at a time

what goes into x^3 mult. by x which would be x^2, so you put x^2 on top of the division bar, and then x^2 times x-1 equals x^3-x^2, and you subt. from your problem which leaves 3x^2+3x-6….then what times x equals 3x^2 which would be +3x which goes beside x^2, so then you mult and that equals 3x^2-3x and you subtract and are left with 6x-6, then you do the same thing get +6 to put on top of bar, multiply and get 6x-6, subtract and get 0 and you’ve solved the problem

x^3 + 2x^2+3x-6

you can check by multiplying your answer by x-1 to see if you get the original problem

then the next problem

do the same thing and you get n^2+3n+9

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hayharbr
On th first just divide the top by the bottom. On the second, factor (n^3 – 27) which is (n-3)(n^2 + 3n + 9) then if n isn’t 3, cancel the n-3
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