How do I solve this problem?
How many liters of a 12% solution must be mixed with a 40% alcohol solution to make a 12 liter solution that is 30% alcohol?
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let x = the number of liters of 12% solution.
12-x = the number of liters of 40% solution
then the equation becomes
12%(x) + 40%(12-x) =30%(12) or 12x+40(12-x) = 30(12)
multiply out: 12x+480-40x=360
combine like terms with x on one side: 28x=120
x= 120/28 or 30/7 liters.
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