help ! i need help with simplifying mixed numbers?

For additon and subtraction, treat the integers separately from the fractions. If the second fraction in a subtraction is larger than the first, reduce the integer part of the first number by 1 and add it into the fraction:

7 2/3 – 2 3/4

= 6 5/3 – 2 3/4.

Put the fractions over a common denominator to add or subtract them.

For multiplication, convert each mixed number to an improper fraction. Multiply the numerators together, and multiply the denominators together. Reduce the resulting improper fraction to its lowest terms, and convert it back to a mixed number.

For division, convert each mixed number to an improper fraction. Invert the second one, and multiply instead of dividing.

Simplifying A Mixed Number

ok first, you turn it right into a mixed quantity. The denominator is for you in looking an entire quantity by potential of multiplying 6 to a quantity that’s closest to or equivalent to the numerator, that’s sixteen. The quantity which you multiply to 6 that isn’t bypass over sixteen is two and it equals 12. there grew to become into no quantity you need to multiply to 6 that is equivalent to sixteen. So now 2 may be the full quantity interior the mixed quantity. Now you subtract 12 from sixteen to have 4 left on the numerator and now the mixed quantity so a ways is two 4/6. The mixed quantity can nonetheless be simplified because of the fact the fraction 4/6 could be simplified because of the fact 4 and six are the two divisible by potential of two. the appropriate answer could now be 2 2/3. wish this permits you =D

Multiply the denominator by the whole number and add the numerator. This is the numerator and the denominator would stay the same. this gives you the improper fraction.

I know a site that will help you…

http://www.algebrahelp.com/lessons/

frg