f=(x^2+1)(x-3) how would i compute the derivative of this function and simplify the answer?

f=(x^2+1)(x-3)

to derive it first got to multiply both the parts in the bracket

it becomes…….

f=x^3-3x^2+x-3

derive it………..

=3x^2-6x+1

Like John pronounced, you basically could desire to apply the formula you’ve been given on any calculus direction. f(x) = ln 2x So first we use the certainty that if f(x)=ln x then f ‘(x) = a million/x f(x) = ln 2x so f ‘(x) = 2/2x = a million/x For the subsequent 2 derivatives we use the certainty that if f(x) = x^n then f ‘(x) = nx^(n-a million) f ”(x) = -a million/x^2 = -x^(-2) f ”'(x) = 2/x^3 = 2x^(-3) If it is an element of your coursework make certain you realize it, by fact basically copying it is going to do you no solid in any respect.

simply expand the function as

f(x) = x^3-3x^2+x-3

then f'(x) = 3x^2-6x+1

u can use u v method to solve this prob… which takes the formula (udv+vdu)…. or els u can simplyfy the anser by multiplin whole tin and de final answer ill b (3x^2+6x+1)