Exercises on Inequalities in Two Variables..pls help me..?

the domain is the possible values x and y can have.

i will do #1

x + y > 8

2 2 = 4 no

2 3 = 5 no

…

2 6 = 8 no (not >y

2 7 = 9 OK

if x = 2, y =9 is only solution… (2,9) is in the set.

repeat for other values of x….

however, it is probably easier to solve for one variable to see what you need, i.e.,:

y > 8 – x

x = 2, y > 6… y = 7 only………. (2,7)

x = 3, y > 5, y = 6, 7……………(3,6), (3,7)

x = 4, y > 4…. ……………………..(4,5), (4,6), (4,7)

x = 5, y > 3 ………………………(5,4) (5,5), (5,6), (5,7)

x = 6, y >2 (6,3), (6,4)..to (6,7)

x = 7, y >1 (7,2), (7,3)…. to (7,7)

repeat same concept for #2 and #3

g.l.

i’m no longer an authority in this, yet I performed with it for exciting. a^b + b^a > a million ln(a^b + b^a) > ln(a million) ln(a^b) + ln(b^a) > 0 b*ln(a) + a*ln(b) > 0 b*ln(b) > -a*ln(a) (expr a million): b*ln(b)/a*ln(a) > -a million notice that: ln(x) = 0 for x = a million ln(x) > 0 for x > a million ln(x) < 0 for x >= 0 < a million ln(x) approaches -infinity while x approaches 0 ln(x) is imaginary for x < 0 So if a and b are > a million then expr a million is authentic And if a and b are > 0 < a million then expr a million is authentic. And if a and b = 0 then expr a million is authentic. And if a and b = a million then expr a million is authentic And if b = a million and a > 0 expr a million is authentic And if a or b < 0 then expr a million is fake if b > a million and a >=0 < a million it gets tricky: if b*ln(b) >= a million and -a million < a*ln(a) < 0 then expr a million would be fake If b >= a million.763 and a < a million then expr a million is fake So: if b > a million.763 and a > a million then expr a million is authentic it sort of feels as though there are limitless opportunities and quite a number of alternative diverse stages of values which will paintings. i think i’m uncertain what “belonging to (0,a million)” capacity precisely. replace: If a and b are > 0 < a million then expr a million is authentic by fact the LHS of expr a million will continuously be helpful and subsequently extra advantageous than RHS of expr a million (-a million).