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Tim D

center (-2,1), radius=4 what is the equation for this one?

center (-2,1), radius=4 what is the equation for this one?

Top 3 Answers
buoisang

Favorite Answer

equation for a circle

(x +2)^2 + (y-1)^2 = 16

form: (x-h)^2 + (y-k)^2 = r^2

(h, k): center

r: radius

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equation of a circle

(x – h)^2 + (y – k)^2 = r^2

the center is (h,k)

r = radius

(x – (-2))^2 + (y – 1)^2 + 4^2

(x + 2)^2 + (y – 1)^2 = 16

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vlee1225
(x+2)^2 + (y-1)^2 = 16

or

(x+2)(x+2) + (y-1)(y-1) = 16

or

x^2 + 4x + 4 + y^2 -2y + 1 =16

x^2 + 4x + y^2 – 2y -11 = 0

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