Another Math Problem!! Please Help!!?

Every -1 degree adds 30 calories lost. Slope = -30x. y = -30x + 3000

Draw a graph of the line. When you draw this have one axis marked in units of 250, and the other in 30.

use the points you know to draw the graph, extrapolate it to get the intercept with the x axis and use the point slope form or Y = mx + b.

You have to trust Lansburg for the linear nature of the relationship. I would guess that the real relationship is not linear.

Use rise/run to calculate the slope (it just could be 1/30 – what do you think)

okay u know it is linear because ever 1 degree lower, 30 calories increase.this is a constant rate which means ull have a straight line. ur slope would be 30 because it would be 30 calories over every 1 negative degree. \

your equation would need to be in y=mx + b

so far it would be y=30x + b

the you need to substiture something for x and y that is a coordinate on the graph. x would be 30 and y would be 1 so

1=30(30) +b

1=900+b

-899=b

equation = y=30x-899

ps)not positive equations right

Since they say “calories varie with temp”, then I would make calories the y-axis, and

temp the x-axis. Then the slope of the line is rise over run. Rise on the y-axis (calories) versus (divided by) run on x-axis.

Like draw a step of stairs on the line.

And use the height of the steps divided by the length of the steps for the slope.