Agebra Graphing questions?
Graph using the intercept method: 5x – y = 5
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then it is in the form y=mx+b
b is the intersection on the y axis so in this problem it intersects at -5 or the point (0, -5)
m is the slope so in this problem it is a slope of 5. Our teachers always told us to think of the slope as “rise over run” so in this problem you would start from the point (0,-5) and go up 5 over 1
(if the problem had been y=3/2x+2 you would start at (0,2) and go up 3 over 2)
5x-(0)=5
so, x=1
y-intercept where x=0, so plug in a zero for x to get the y-intercept:
5(0)-y=5
y=-5.
the slope is always the number before x because the formula mx+b=y (the m is the slope), so here 5 is the slope.
on your graph find -5 on the y-axis (or point (0,-5)) and do rise/run (up 5 over to the right 1) and you will see your next point is (1,0), which will confirm you are correct because the x-intercept is 1.
