a boy kicks a football w/ an initial velocity component of 15.0m/s & a horizontal velocity component of 22m/s.
..cont..
a) what is the initial velocity of the football (magntiude & direction)?
b) how much time is needed to reach he maximum height?
c) how high is that point?
2.) a shooter fires a rifle at a target 60m away w/ a muzzle velocity (the velocity at w/c bullet leaves the gun) of 300m/s. His rifle is 2.0m above the ground when fired horizontally. At what height should the target be placed above he ground in order to be hit by the shooter?
need you help guyz…thanx..
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1a♦ |V|= sqrt(15^2+22^2) m/s; angle=atan(15/22) rad;
b♥ 15=g*t, hence t=15/9.8 s;
c♣ h=0.5*g*t^2 = 0.5*9.8*(15/9.8)^2 m;
2♠ time to target t=60/300 =0.2 s; in this time the bullet will be h=0.5g*t^2 below the rifle; target be placed at 2-h meters;
almost no hope it helps though!
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