Square root of (3x^2) = 3x-2?
ok. will someone work this for me? i’m checking my problems.
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sqrt(3x^2)=3x-2
square both sides
3x^2=(3x-2)^2
3x^2=9x^2-12x+4
6x^2-12x+4=0
This is of form ax^2+bx+c=0
There are 2 solutions
x=[-b+sqrt(b^2-4ac)]/2a
=[-(-12)+sqrt(144-96)]/12
=[12+sqrt(48)]/12=19/12 (approximately)
The other root is
[12-sqrt(48)]/12=5/12 (approximately)
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sqrt(3x^2) means the square root of 3.x.x
which means x . sqrt3
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I believe its 3x cause 3X^2 = 3x * 3x
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3x^2 = 3 * x^2
Sqrt(3 * x^2) = Sqrt (3) * sqrt(x^2) = x * sqrt(3)
Final answer would be
x * Sqrt(3)
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