Law of Sines: Solve Trianlges?
Use the law of sines to solve for triangles. If two solutions exist find both of them:
a. A=38 degrees , a=19.3 , b=10.5
b. A=52 degrees , a=6.4 , b=7.2
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A=38 degrees , a=19.3 , b=10.5
Sin38/19.3 = SinB/10.5 = SinC/c
Therefore SinB = Sin38*10.5/19.3 and
B = ArcSin(Sin38*10.5/19.3) = 19.569 degrees
C = 90 – 38 -19.569 = 32.4308 degrees.
From above c/SinC = 19.3/Sin38
Therefore c = 19.3SinC/Sin38
c = 19.3Sin32.4308/Sin38 = 16.8115
Use the identical method to solve the next problem.
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