perimeter of a rectangular?
writing pad is 28 in the length is 1 inch less than twice the width find the width
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If the perimeter of the rectangle is 28in, then the equation would be 28 = 2[(2x-1)+x] where x is the width of the rectangle. The length is 2x-1 because the length is one inch less than twice the width. Just distribute and solve for x.
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Eh… Not quite sure how to write it out, but I’ll try anyways.
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Rectangle Perimeter = 2 (W) + 2 (L)
W = X, L = 2X – 1
2 ( X ) + 2 (2X – 1) = 28 in
2X + 4X – 2 = 28 in
6X – 2 = 28 in
6X = 30
X = 5
Width of the Writing Pad is 5 inches.
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5 years ago
The width of the rectangle should be 56 feet In a rectangle the two lengths equal 176 feet total You subtract the 176 from the 294 feet that leaves you 118 feet You divide the 118 feet by 2 for the 2 sides and you get 56 feet for each side width
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length is 2(width)-1
width = x
perimeter of rectangle is 2(length) + 2(width)
2(2x-1) + 2x=28
4x-2+2x=28
6x-2=28
6x=30
x=5
width is 5
length is 2(5)-1=10-1=9
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P= 2L + 2W
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