Write an equation for the locus of points equidistant from (2,-3) and (6,1). What is this equation?
It’d be great for the answer, but just some help to steer me in the right direction would be good too.
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If you draw the line segment connecting those two points, its midpoint is equidistant from each of them. Also, EVERY point on the PERPENDICULAR BISECTOR of that line segment will be equidistant from each endpoint.
To find its equation, find the slope of a line perpendicular to the line segment connecting the two points (negative reciprocal) and find one point on the line (the midpoint) and then you can use the point-slope form of a line.
I hope this helps!
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4 years ago
y = 3 is the equation of a right now (horizontal) line at a relentless distance 3 above the x-axis. y = -5 is the equation of a right now (horizontal) line at a relentless distance of five under the x-axis. The equidistant line will lie midway between those 2, at y = -a million y = 2 is the equation of a right now (horizontal) line at a relentless distance 2 above the x-axis. y = -4 is the equation of a right now (horizontal) line at a relentless distance of four under the x-axis. The equidistant line will lie midway between those 2, at y = -a million
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