Rationalize the denominator: 2/√[3] + √[2]?

So, first our equasion looks something like this. (oh, how I hope this formats right…)

2

————-

√[3] + √[2]

Now, we need to eliminate the square roots from the bottom…you can do this by using the conjugate (what is a conjugate? if the equasion is a+b, the conjugate would be a-b) over the conjugate.

So, the conjugate of √[3] + √[2] would be √[3] – √[2].

Since any number over itself is one, we can multiply by (√[3] – √[2]) / (√[3] – √[2]).

Then, we’re left with

2(√[3] – √[2]) / (3 + 2)

When multipled, that’s 2√[3] – 2√[2] / 5

There ya go! Denominator is now rationalized!

If you have any more questions, this page is great at explaining everything: http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut41_rationalize.htm