Help with this math problem?
A farmer purchases cows for 10 dollars each, pigs for 3 dollars each, and chickens for 50 cents each, he buys exactly 100 animals total, and spends exactly 100 dollars, if he buys at least one of each animal, how many of each does he buy?
thanks,
Olivia
Top 4 Answers
Favorite Answer
94 chickens *.50= $47.00.
1 pig * 3.00=$ 3.00.
5 cows * 10.00=$50.00.
——————————————
100 animals =$100.00
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You’ll have to setup some sort of eqaution to make this possible
A table would be best using x to identfy your smallest quantity (chickens)
chickens are $.5 each (.5x)
then extrapolate the x to the other values
cost of 6 chickens is one pig (6x)
cost of 20 chickens is one cow (20x)
so .5x + 6x + 20x = $100
26.5x = 100
x = 3.77
.5x = 1.885 chickens
6x = 22.62 pigs
20x = 75.4 cows
99.905 total animals
not exact, so there might be flaw in how the problem was asked. Very close though
Edit note: I am reworking this on paper, after I noticed that I had 77 cows ($770).
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I don’t think there is an answer for this question. Its impossible. If he buys 1 of each, so far he’ll have 86.50 dollars left, and 97 animals to go. So the cheapest is 97 chickens, but that will equal 48.50, and add those together is $135! That’s over $100, and thats 100 animals. If I’m wrong, I’m sorry.
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9 cows. 3 pigs, 2 chickens…
90+9+1 =100
There are other combinations but this one is easy 🙂
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