Simplify: √[81x12y8z10]?
Simplify: √[81x12y8z10]?
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factor each number 81=9*9;12=3*4;8=2*4;10=5*2…then take one number from each pair and multiply (9*4*2) and that equals your number on the left side of the squareroot (72) then the rest goes inside the square root (15xyz) ….
72(squareroot)[15xyz]
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Here is a way to write this out:
â[ 9*9*xxxxxxxxxxxxyyyyyyyyzzzzzzzzzz]
Each time you have a square root of something squared, you get one of those things. So you have one pair of 9s, six pairs of xs, four pairs of ys and five pairs of zs. Therefore your answer is
9x^6y^4z^5
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9x^6y^4z^5
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