Simplify these algebra problems please!?
1. √1/6
2. √1/125
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I’m guessing the whole fraction is under the square root……
1. sqrt(1)/sqrt(6)
==>multiply by sqrt(6)/sqrt(6)
sqrt(6) / 6
2. sqrt(1)/sqrt(125)
sqrt(1)/5sqrt(5)
==>multiply by sqrt(5)/sqrt(5)
sqrt(5)/25
1
1. â(1/6)
= â (1/6)x(6/6)
= 6â6
2. â1/125
= 1/5
the top one you cannot have a number on the bottom so you must multiply it by something that will give it its squared factor so it is simple to remove from being squared… you do 6/6 because it is equal to 1…this doesn’t effect the problem because anything multiplied by 1 is the same…
the second one is just (1/5)^2 so it is very simple
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assuming sqroot(1/6) or sqroot(1/125).
q is quareroot (your chkmark).
q(1) / q(6)
1 / (q(6) = q(6)/6
q(1/125) =
1/q(5*5*5) =
1/5*q(5) =
q(5) /25
Depending on teacher many dont want the sqrt left on bottom.
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