Tough question: Determine graphically the vertices of a triangle whose sides are:?
y=x, y=0 and 2x + 3y = 10. I found the first two vertices (0,0) and (5,0), but I don’t know how to find the third or how to graph the solutions. Please help!!!
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the line y=x and 2x + 3y = 10 will intersect at the point where y=x….
so just plug y=x into the 2x+3y = 10 and you will get…
when y = x…
2x+3y = 10
2x + 3(x) = 10
2x + 3x = 10
5x = 10
x = 2…
since we know that x = y…. therefore the 3rd vertice is at point (2,2)
you could have also plugged x = y… and you will still get the same answer…
when x = y…
2y+3y = 10
2y + 3(y) = 10
2y + 3y = 10
5y = 10
y = 2…
since we know that x = y…. therefore the 3rd vertice is at point (2,2)
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Hey Kid,
You had the answer all along… Since y=x originates at (0,0) that is one of the point..
Solve 2x+3y=10 and y=x together
you will get (2,2) which is the second point that you are missing.
The third point is (5,0), as you have correctly got
Hope that helps…
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