um graphing functions?
how do u do this?
Graph y=x^2+6
Give the domain and range
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Its a parabola.
The domain is infinite. The range is y is greater than or equal to 6
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for it to be a function, you may have no more than one x-value for each y-point (in other words, no duplicate x-values with the same y-values), right? an easy way to work this out is to graph it, just a quick sketch. you should be able to draw a vertical line anywhere on this graph and the line should only intersect your graph once, otherwise it’s not a function. this isn’t a problem with this equation so your domain, which deals with your x-values can be any real number ( D = {R}). however, this is a parabola, so it has a vertex, meaning you will have to restrict your range (dealing with the y-values). so find your vertex. it’s already in vertex form { y = a(x – h)^2 + k }, just simplified a bit ( a = 1, k = 0 ). your vertex is (h, k) so: (0, 6). you know this parabola opens up because “a” is positive. this means that you will have no y-values less than 6. therefore your range is: R = {y/y >\= 6, y E R}.
*>\= means “greater than or equal to”, and the “real number” symbol (R) should have the two vertical sticks, just not sure how to do that with a keyboard.
hope that helps.
(sorry, mistake in the range, now fixed, my bad)
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