2n^2 – 2n – 1 = 0 How do i solve for n, and prove my answer is correct?
2n^2 – 2n – 1 = 0 How do i solve for n, and prove my answer is correct?
Top 3 Answers
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Solve by quadratic equation:
n= [-b±(b²-4ac)^½]÷2a where:a=2, b=-2, c=-1
n= [-(-2)±(-2² – (4)(2)(-1))^½÷(2)*(2)
n= [+2±(4+8)^½]÷4
n=(2±3.464)÷4
n=5.464÷4=1.366
or n= -1.464÷4= -0.366
check:
1) 2(1.366)²-2(1.366)-1=0
3.731-2.732-1=0
1-1=0
2) 2(-0.366)² – 2(-0.366) -1=0
0.267+0.732-1=0
1-1=0
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To solve for n, factor it out. And then plug in n in the equation to prove it.
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Use the quadratic equation: -b +/- sqrt(b^2-4ac)/2a
The answer will be n which you prove by plugging into the equation.
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