21x^3-18x^2-7x+6?
Factor by grouping
Top 4 Answers
Favorite Answer
21x^3-18x^2-7x+6
=3x^2(7x-6)-1(7x=6)
=(3x^2-1)(7x-6)
=(x*3^1/2-1)(x*3^1/2+1)(7x-6)
(x*3^1/2-1)(x*3^1/2+1)(7x-6) are the factors of the given eqn.
0
There is a program called Algebrator. It is a program that pretty much has the ability to go step by step through the problem.
Here is what I got using the Algebrator.
(7x-6)(3x^2-1)
0
rearrange:
21x^3-7x-18x^2+6
factor out:
7x(3x^2-1)-6(3x^2-1)
group together:
=(7x-6)(3x^2-1)
0
(21x^3 – 18x^2) – (7x – 6)
3x^2(7x-6) – 1(7x-6)
(3x^2 – 1)(7x-6)
0
